# 一題度量空間證明 (有關closure)

Prove: (a) \\bar{A∪B} = \\bar{A}∪\\bar{B}; (b) \\bar{\\bar{A}} = \\bar{A}

(\\bar{A} 就是在A上方加一條橫線，這裡代表closure of A，其定義請見下方。)

metric function 和 metric space 的定義：

Suppose that there exists a real-valued function ρ defined for every ordered pair (x, y) of points of the universal set X, having the following properties:

(i) ρ(x, y) ≧ 0, and ρ(x, y) = 0 if and only if x = y.

(ii) ρ(x, y) = ρ(y, x) (symmetry).

(iii) ρ(x, z) ≦ ρ(x, y) + ρ(y, z) (the triangle inequality).

The function ρ is then called a metric function (or a distance function) on X, and the pair (X, ρ) is called a metric space.

open ball 的定義：

For any x∈X, ε>0, the set

B(y, ε) = {y; ρ(x, y) < ε}

is called the open ball with center y and radius ε, or an ε-neighborhood of y.

A set E is called an open set if for any y∈E there is a ball B(y, ε) that is contained in E.

A set is said to be closed if its complement is an open set.

accumulation point 和 closure的定義：

A point y is called a point of accumulation of a set D if any ball B(y, ε) contains points of D other than y.

Denote by D\' the set of all the points of accumulation of D.

The set D∪D\' is called the closure of D, and it is denoted by \\bar{D}.

### 1 個解答

• 1 0 年前
最佳解答

由於closure的符號太難打,我把它簡化成'先給個Lemma:If A包含於B,則A'包含於B'證明:這很trivial!,Let ε>0 be given,x　屬於A',there exists y屬於A,such that ρ(x,y)<ε,so y屬於A,y屬於B,that is , there exists y屬於B,such that ρ(x,y)<ε,Hence x屬於B' ie A'包含於B'(a)since A包含於A∪B,B包含於A∪B,so A'包含於(A∪B)',B'包含於(A∪B)'=>A'∪B'包含於(A∪B)'Suppose that x屬於(A∪B)',let ε>0 be given,there exists y屬於A∪B,such that ρ(x,y)<εthat is there exists y屬於A,or y屬於B,such that ρ(x,y)<εx屬於A' or 屬於B'=>(A∪B)'包含於(A'∪B')=>(A∪B)'=A'∪B'(b)We know A包含於A',so A'包含於(A')'Now,geven any ε>0,x屬於(A')',there exists y屬於A' such that ρ(x,y)<ε/2But y屬於A',there exists z屬於A such that ρ(y,z)<ε/2so,there exists z屬於A such that ρ(x,z)≦ρ(x,y)+ρ(y,z)<ε/2+ε/2=ε＝＞x屬於A'=>(A')'包含於A'=>(A')'=A'

參考資料： me
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