七月 發問時間: 社會與文化語言 · 1 0 年前

請求英文高手 救救英文白癡 幫忙翻譯這一段

Consider a processor operating at 1GHz (1 ns clock) connected to a DRAM with a latency of 100 ns (no caches)= 100 cycles.

Assume that the processor has two multiple-add units and is capable of executing four instructions in each cycle of 1 ns. The peak processor rating is therefore 4 GFLOPS.

(4 FLOPS/cycle x 109 cycles/s=4x109FLOPS)

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  • 1 0 年前
    最佳解答

    Consider a processor operating at 1GHz (1 ns clock) connected to a DRAM with a latency of 100 ns (no caches)= 100 cycles.

    考慮在被連接到一個 100 ns(沒有隱藏所)的潛伏動態隨機存取記憶體的 1GHz(ns 時鐘)操作的一個處理器=100個周期。

    Assume that the processor has two multiple-add units and is capable of executing four instructions in each cycle of 1 ns. The peak processor rating is therefore 4 GFLOPS.

    (4 FLOPS/cycle x 109 cycles/s=4x109FLOPS)

    假設,處理器在1 ns的每個週期安排二多增加單位並且是能執行四指示。

    因此高峰處理器規定值是4 GFLOPS。

    (4 FLOPS/cycle x 109 cycles/s=4x109FLOPS)

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