Tim Yeh 發問時間： 電腦與網際網路程式設計 · 1 0 年前

可以請哪位高手幫我寫這個程式嘛@@??

(No: 0, 2, 4, 6, 8) (20 points) Write a program that reads the coefficients, a, b, and c of the equations ax2 + bx + c = 0 and calculates the roots of the equation. You need to consider the situation when there is no solution of real numbers.

Hint: Use the sqrt and fabs function.

A sample run is shown as below:

Enter the coefficents of the equation (a, b, c): 1 -3 2

x = 2.0 and x = 1.0

Enter the coefficents of the equation (a, b, c): 0 1 2

x = -2

Enter the coefficents of the equation (a, b, c): 1 2 3

There is no solution.

1 個解答

• 1 0 年前
最佳解答

#include <stdio.h>

#include <stdlib.h>

#include <math.h>

main()

{ float a,b,c,d;

printf("Enter the coefficents of the equation (a, b, c): ");

scanf("%f%f%f",&a,&b,&c);

d=b*b-4*a*c; /* 判斷式 */

if(a==0)

printf("x=%0.1f\n",-1*c); /* 若為一次方程式 */

else

{ if(d>=0)

{ if(d==0) /* 重根 */

printf("x=%0.1f\n",(-b+sqrt(d))/(2*a));

else /* 相異實根 */

printf("x=%0.1f and x=%.01f\n",(-b+sqrt(d))/(2*a),(-b-sqrt(d))/(2*a));

}

else /* 無實根 */

printf("There is no solution\n");

}

system("pause");

}

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