C語言乘法的程式
(用C語言寫)
撰寫一個學習乘法的程式，程式會利用rand來產生兩個個位正整數，然後印出如以下的問題：
How much is 6 times 7?
在使用者將答案鍵入後程式會檢查，並依對錯印出不同的評語。
正確答案的評語：
Very good!
Excellent!
Good job!
Keep up the good work!
錯誤答案的評語：
No. Please try again.
Wrong. Try once more.
Don＇t give up!
No. Keep trying.
請使用1到4的亂數和switch結構對每個答案選擇適當的評語 (如圖一) ；錯的答案要再回答一次(如圖二)。
Enter -1 to end.
How much is 4 times 1? 4
Keep up the good work!
How much is 4 times 0?
圖一
Enter -1 to end.
How much is 2 times 7? 13
No. Keep trying.
How much is 2 times 7? 14
Very good!
How much is 9 times 5?
圖二
Atilla :
你是用C++寫嗎??
我沒學過C++耶~
看不太懂,
能不能用C語言寫?
謝謝~
3 個解答
- 達達Lv 51 0 年前最佳解答
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
int A,B,key;
printf("Enter -1 to end.\n");
srand(time(NULL));
A=rand()%10;
B=rand()%10;
while(key!=-1)
{
printf("How much is %d times %d?",A,B);
scanf("%d",&key);
if(key==A*B&&key!=-1)
{
A=rand()%10;
B=rand()%10;
switch(rand()%4+1)
{
case 1:printf("Excellent!\n");break;
case 2:printf("Good job!\n");break;
case 3:printf("Keep up the good work!\n");break;
case 4:printf("Very good!\n");break;
}
}
else if(key!=-1)
switch(rand()%4+1)
{
case 1:printf("Wrong. Try once more.\n");break;
case 2:printf("Don’t give up!\n");break;
case 3:printf("No. Keep trying.\n");break;
case 4:printf("No. Please try again.\n");break;
}
}
return 0;
}
- 匿名使用者1 0 年前
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main()
{
int num1,num2,answer,response,x,y;
srand(time(NULL));
do{
num1=1+rand()%9;
num2=1+rand()%9;
printf("How much is %d times %d ?\n",num1,num2);
answer=num1*num2;
do{
printf("The answer is(-1 to end):");
scanf("%d",&response);
if(response==-1)
break;
if(answer!=response){
x=1+rand()%4;
switch(x){
case 1:printf("No.Please try again.\n\n");
break;
case 2:printf("Wrong. Try once more.\n\n");
break;
case 3:printf("Don't give up!\n\n");
break;
case 4:printf("No. Keep trying.\n\n");
break;
}
}
}
while(answer!=response);
if(answer==response){
y=1+rand()%4;
switch(y){
case 1:printf("Very good!\n\n");
break;
case 2:printf("Excellent!\n\n");
break;
case 3:printf("Nice work!\n\n");
break;
case 4:printf("Keep up the good work!\n\n");
break;
}
}
}
while(answer==response);
system("pause");
return 0;
}
參考資料： 經驗 - 1 0 年前
我沒有設計防其他按鈕(非數字)，例如輸入英文或是其他字元
#include <iostream>
#include <math.h>
#include <time.h>
using namespace std;
int main(void);
int main(void){
int x, y, key;
int input;
bool getnumber = 1;
srand(time(NULL));
cout << "Enter -1 to end." << endl;
do{
if(getnumber){
x = rand()%9 + 1;
y = rand()%9 + 1;
}
key = rand()%4 + 1;
cout << "How much is " << x << " times " << y << " ? ";
cin >> input;
if(input == -1)
break;
else if(input == x*y){
getnumber = 1;
switch(key){
case 1:
cout << "Very good!" << endl;
break;
case 2:
cout << "Excellent!" << endl;
break;
case 3:
cout << "Good job!" << endl;
break;
default:
cout << "Keep up the good work!" << endl;
}
}else{
getnumber = 0;
switch(key){
case 1:
cout << "No. Please try again." << endl;
break;
case 2:
cout << "Wrong. Try once more." << endl;
break;
case 3:
cout << "Don’t give up!" << endl;
break;
default:
cout << "No. Keep trying." << endl;
}
}
}while(1);
// system("pause");
return 0;
}
2008-01-09 14:59:23 補充：
其實C 跟 C++ 沒有差很多，因為工作要用C++所以我習慣上也就用C++的方式回答
這裡面的寫法只有cout 跟 cin 這兩個妳不知道吧
其實就是printf 跟 scanf
2008-01-10 10:29:32 補充：
達達回答的也很正確，但是有個缺點，就是
while(key!=-1)
因為它只有宣告key卻沒有給起始值直接判斷是不是等餘-1
或許你會覺得這樣沒有錯，而且執行也不會錯，但是，對於我們程式設計師們來說這是個很嚴重的事情，因為有可能key在你沒設定起始值的時候它會剛剛好是 -1 (雖然發生機率很低，但是還是要注意)