? 發問時間: 社會與文化語言 · 1 0 年前

[高中數學]英文版--機率part3

1. a) Starting with a group of 6 girls and 4 boys, how many ways could you make a committee containing 4 people?

b) How many ways if the committee must contain two girls and two boys?

c) How many ways if the committee must include Candace but does not include Ronald?

2. a) A card is selected from a well shuffled deck of cards. What is the probability that the card is red?

b) What is the probability that it is a seven or a jack?

c) What is the probability that it is a face card?

d) What is the probability that it is a red ace, a five, or a black three?

20點大贈送..謝謝!!

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  • 1 0 年前
    最佳解答

    1. a) Starting with a group of 6 girls and 4 boys, how many ways could you make a committee containing 4 people?

    10*9*8*7 = 5,040 ways.

    b) How many ways if the committee must contain two girls and two boys?

    6*5*4*3 = 360 ways.

    c) How many ways if the committee must include Candace but does not include Ronald?

    Candace must be in, so three spots left. Ronald can't be in, so 8 persons left to be selected. So, 8*7*6 = 336 ways.

    2. a) A card is selected from a well shuffled deck of cards. What is the probability that the card is red?

    P(red) = 26/52 = 50%

    b) What is the probability that it is a seven or a jack?

    P(7 or J) = 8/52 = 15.38%

    c) What is the probability that it is a face card?

    Face cards: K or Q or J from ♥, ♠, ♣, and ♦ = 12

    P(face card) = 12/52 = 23.08%

    d) What is the probability that it is a red ace, a five, or a black three?

    The set of {a red ace, a five, or a black three} include: ♥A, ♦A, ♥5, ♦5, ♠5, ♣5, ♠3, ♣3 = 8 cards.

    P(a red ace, a five, or a black three) = 8/52 = 15.38%

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