請問為什麼我的c語言程式無法執行呢?
這是程式
Write a program that reads three nonzero integers and determines if they can represent the sides of a right triangle. If they can, please print “Yes, they form a right triangle.” and print the rectangle with two legs of the right triangle; otherwise, please print “No, they do NOT form a right triangle.”.
Sample of the program execution:
Please input 3 integers: 5 12 13
Yes, they form a right triangle.
************
************
************
************
************
Or
Please input 3 integers: 7 8 9
No, they do NOT form a right triangle.
這是程式碼
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int a,b,c,j,i;
printf("Please enter three integers:");
scanf("%d%d%d",a,b,c);
if(a*a==b*b+c*c||b*b==a*a+c*c||c*c==a*a+b*b)
{
printf("Yes, they form a right triangle");
}
else
{
printf("No,they do not form a right triangle");
}
if(a>b>=c||a>c>=b)
{
for(i=1;i<=c;i++)
{
for(j=1;j<=b;j++)
{
printf("*");
}
printf("\n");
}
}
else if(b>a>=c||b>c>=a)
{
for(i=1;i<=c;i++)
{
for(j=1;j<=a;j++)
{
printf("*");
}
printf("\n");
}
}
else if(c>b>=a||c>a>=b)
{
for(i=1;i<=b;i++)
{
for(j=1;j<=a;j++)
{
printf("*");
}
printf("\n");
}
}
return 0;
}
1 個解答
- 歌篾Lv 41 0 年前最佳解答
錯誤一[第9行]：
讀入的變數之前需要半形的＆
例如：scanf("%d%d%d",＆a,＆b,＆c);
錯誤二[第19,30,41行]：
C語言不接受像a＞b＞=c的連續比較，所以要改成：
第9行：if((a＞b＆＆b＞=c)||(a＞c＆＆c＞=b))
第30行：else if((b＞a＆＆a＞=c)||(b＞c＆＆c＞=a))
第41行：else if((c＞b＆＆b＞=a)||(c＞a＆＆a＞=b))
但事實上，這個問題不需要用這麼複雜的邏輯，您只要用下面幾行就夠了：
#include ＜stdio.h＞
#include ＜stdlib.h＞
int main(void)
{
int a,b,c,i,j,hyp,leg1,leg2;
printf("Please enter three integers: ");
scanf("%d%d%d",＆a,＆b,＆c);
hyp=max(a,max(b,c));
leg1=min(a,min(b,c));
leg2=a+b+c-hyp-leg1;
if(hyp*hyp==leg1*leg1+leg2*leg2)
{
printf("Yes, they form a right triangle.\n");
for(i=1;i＜=leg1;i++)
{
for(j=1;j＜=leg2;j++)
printf("*");
printf("\n");
}
}
else
printf("No, they do not form a right triangle.\n");
return 0;
}
2008-12-17 01:05:32 補充：
抱歉，上面的出現了一些亂碼，我重新再post一次 (請把＼＞＜＆＂改成半形)：
#include ＜stdio.h＞
#include ＜stdlib.h＞
2008-12-17 01:05:41 補充：
int main(void)
{
int a,b,c,i,j,hyp,leg1,leg2;
printf(＂Please enter three integers: ＂);
scanf(＂%d%d%d＂,＆a,＆b,＆c);
hyp=max(a,max(b,c));
leg1=min(a,min(b,c));
leg2=a+b+c-hyp-leg1;
2008-12-17 01:05:47 補充：
if(hyp*hyp==leg1*leg1+leg2*leg2)
{
printf(＂Yes, they form a right triangle.＼n＂);
for(i=1;i＜=leg1;i++)
{
for(j=1;j＜=leg2;j++)
printf(＂*＂);
printf(＂＼n＂);
}
}
else
printf(＂No, they do not form a right triangle.＼n＂);
return 0;
}
