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- 浮浪貢Lv 71 0 年前最佳解答
x^3 * (1+x^2)^1/2的積分值
u=1+x^2, du=2xdx
sx^3 * (1+x^2)^(1/2)dx
=(1/2)s x^2((1+x^2)^(1/2)*2x dx
=(1/2)s (u-1)u^(1/2)du
=(1/2)s u^(3/2)- u^(1/2)du
=(1/5)u^(5/2)-(1/3)u^(3/2)+C
=(1/5) (1+x^2) ^ (5/2) -(1/3) (1+x^2) ^(3/2)+C
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