發問時間: 科學其他:科學 · 9 年前

量子物理問題 求高手幫忙!!有解答缺詳解!!~

6.8 Prior to the discovery of the neutron in 1934 it was believed that the nucleus consisted of protons and electrons. For example, 4He was envisaged as a composite of four protons and two electrons confined within the nuclear radius. What would be the kinetic energy of an electron confined within a sphere of 4 x 10^-15 m diameter, the typical diameter of a light nucleus? Is that result consistent with the energies of electrons emitted in " decay, which range from a few ke V to about 1 Me V?

KE=p^{2}/2m=\frac{(\bigtriangleup p)^{2}}{2m}=(h'/2\bigtriangleup R)^{2}/2m=\frac{(hc)^{2}}{32\pi ^{2}(\bigtriangleup R)^{2}mc^{2}}.For

\bigtriangleup R=4fm=4\times 10^{-5}nm.............we...have.....KE\geq \frac{(1240eV\cdot nm)^{2}}{32\pi ^{2}(4\times 10^{-5}nm)^{2}(5.11\times 10^{5}eV)}=600Mev.More...than...100...times...typical....\beta ....energies

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