According to molecular orbital (MO) theory,?
the 12 outermost electrons in the O2 molecule are distributed as follows:
(A) 12 in bonding MOs, 0 in antibonding MOs.
(B) 10 in bonding MOs, 2 in antibonding MOs.
(C) 9 in bonding MOs, 3 in antibonding MOs.
(D) 8 in bonding MOs, 4 in antibonding MOs.
(E) 7 in bonding MOs, 5 in antibonding MOs.
Answer is (D) 8 in bonding MOs, 4 in antibonding MOs.
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(D)is the answer
electronic configuration of O is 1s2 2s2 2p2
O2 will have 12 e
according to MO theory 1s(bonding) 2e, 1s(anti bonding) 2e, 2s (bonding)2e, 2s (antibonding)2e, 2p (bonding)(px py) 4e.
total bonding e = 8
total anti bonding e= 4
bond order is 2
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